📚 Class 11 Mathematics · NCERT Chapter 2

Relations and Functions

From Cartesian products to function graphs — master every concept needed for AAI ATC with clear explanations and MCQ practice.

5
Subtopics
15
MCQs
3
Exercises
📺 Video Lecture — Relations & Functions (Class 11) by AAI ATC Exam Prep
📺 Full video lecture embedded above  |  Subscribe for more free lectures →
Cartesian Product Relations Functions Types of Functions Algebra of Functions
×

2.1 Cartesian Product of Sets

Definition

Given two non-empty sets P and Q, the Cartesian product P × Q is the set of all ordered pairs of elements from P and Q:

P × Q = {(p, q) : p ∈ P, q ∈ Q}

If either P or Q is the null set, then P × Q = φ.

🖼️

[ Image: Arrow diagram of Cartesian product (e.g., colours × objects) — add here ]

Key properties of Cartesian products:

i

If n(A) = p and n(B) = q, then n(A × B) = pq

ii

In general, A × B ≠ B × A (order of the pair matters)

iii

R × R = set of all coordinate points in 2D plane; R × R × R = all points in 3D space

iv

A × A × A = {(a, b, c) : a, b, c ∈ A} — called an ordered triplet

Example: If A = {1, 2} and B = {3, 4}, then A × B = {(1,3), (1,4), (2,3), (2,4)} → n(A × B) = 4

🎯 Practice MCQs

3 Questions
1If n(A) = 3 and B = {3, 4, 5}, then the number of elements in A × B is:
A3
B6
C9
D12
Answer: C
n(A) = 3, n(B) = 3 (elements 3, 4, 5). Using the formula n(A × B) = n(A) × n(B) = 3 × 3 = 9.
2If A × B = {(p,q),(p,r),(m,q),(m,r)}, then n(A) and n(B) are respectively:
A4 and 1
B2 and 2
C1 and 4
D4 and 4
Answer: B
A = set of first elements = {p, m} → n(A) = 2. B = set of second elements = {q, r} → n(B) = 2. And indeed n(A × B) = 4 = 2 × 2 ✓
3If (x + 1, y – 2) = (3, 1), the values of x and y are:
Ax = 4, y = 3
Bx = 3, y = 1
Cx = 2, y = 3
Dx = 1, y = 2
Answer: C
Corresponding elements of equal ordered pairs are equal:
x + 1 = 3 → x = 2
y – 2 = 1 → y = 3
ADVERTISEMENT
R

2.2 Relations

Definition

A relation R from a non-empty set A to a non-empty set B is a subset of the Cartesian product A × B. It is obtained by describing a relationship between the first and second elements of ordered pairs in A × B.

The domain of R = set of all first elements.
The range of R = set of all second elements.
The whole set B = codomain of R. Note: Range ⊆ Codomain.

🖼️

[ Image: Arrow diagram showing a relation between two sets — add here ]

If n(A) = p and n(B) = q, then the total number of possible relations from A to B = 2pq.

eg

Let A = {1,2,3,4,5,6}. R = {(x,y) : y = x+1} = {(1,2),(2,3),(3,4),(4,5),(5,6)}
Domain = {1,2,3,4,5}, Range = {2,3,4,5,6}, Codomain = {1,2,3,4,5,6}

Total relations from A to B = 2^(pq)
Range ⊆ Codomain

🎯 Practice MCQs

3 Questions
4If A = {1, 2} and B = {3, 4}, the total number of relations from A to B is:
A4
B8
C16
D2
Answer: C
n(A) = 2, n(B) = 2. So n(A × B) = 4. Total relations = 2^(n(A×B)) = 2^4 = 16.
5For R = {(x,y) : y = x+1} on A = {1,2,3,4,5,6}, which statement is correct?
ADomain = {1,2,3,4,5,6}
BRange = {1,2,3,4,5,6}
CDomain = {1,2,3,4,5}, Range = {2,3,4,5,6}
DRange = Codomain
Answer: C
R = {(1,2),(2,3),(3,4),(4,5),(5,6)}. First elements (domain) = {1,2,3,4,5}. Second elements (range) = {2,3,4,5,6}. Element 6 is in A but has no image (6+1=7 ∉ A), so 6 ∉ domain.
6The domain of the relation R = {(x, x³) : x is a prime number less than 10} is:
A{1, 8, 27, 125}
B{2, 3, 5, 7}
C{8, 27, 125, 343}
D{2, 3, 5, 7, 11}
Answer: B
Prime numbers less than 10 are: 2, 3, 5, 7. These are the first elements (x values) of the ordered pairs — the domain. The range would be {8, 27, 125, 343}.
ADVERTISEMENT
f(x)

2.3 Functions

Definition

A relation f from set A to set B is called a function if every element of set A has one and only one image in set B.

Written as f : A → B, where f(a) = b means b is the image of a, and a is the preimage of b.

A is the domain, B is the codomain, and the set of all images is the range.

🖼️

[ Image: Arrow diagram comparing function vs non-function — add here ]

When is a relation NOT a function?

If any element of domain has no image in B (e.g., R = {(1,2),(2,3)} on A = {1,2,3} — element 3 has no image)

If any element of domain has more than one image (e.g., R = {(2,2),(2,4),(3,3)} — element 2 maps to both 2 and 4)

A real valued function has R or its subset as range. A real function also has R or its subset as domain.

Function f(x) = 2x + 1 for x = 1 to 7:

x1234567
f(x) = 2x+13579111315

🎯 Practice MCQs

3 Questions
7Which of the following relations is a function?
AR = {(2,2),(2,4),(3,3),(4,4)}
BR = {(1,2),(2,3),(3,4),(4,5),(5,6),(6,7)}
CR = {(1,3),(1,5),(2,5)}
DR = {(1,2),(2,3)} on A = {1,2,3}
Answer: B
In B, each element has exactly one image: 1→2, 2→3, 3→4, 4→5, 5→6, 6→7 — it is a function.
A: element 2 maps to both 2 and 4 (not a function).
C: element 1 maps to both 3 and 5 (not a function).
D: element 3 has no image (not a function).
8If f(x) = 2x – 5, find f(7):
A5
B14
C9
D–5
Answer: C
f(7) = 2(7) – 5 = 14 – 5 = 9.
9The domain of f(x) = (x² + 3x + 5) / (x² – 5x + 4) is:
AR – {1}
BR – {4}
CR – {1, 4}
DR
Answer: C
Denominator x²–5x+4 = (x–1)(x–4). Function is undefined when denominator = 0, i.e., at x = 1 and x = 4. So domain = R – {1, 4}.
ADVERTISEMENT
📈

2.4 Types of Functions and Their Graphs

Seven important types of real functions with their key properties:

① Identity Function

f(x) = x for all x ∈ R. Domain = R, Range = R. Graph: straight line through origin with slope 1.

② Constant Function

f(x) = c (constant) for all x ∈ R. Domain = R, Range = {c}. Graph: horizontal line parallel to x-axis.

③ Polynomial Function

f(x) = a₀ + a₁x + a₂x² + ... + aₙxⁿ where n is a non-negative integer and aᵢ ∈ R. Examples: f(x) = x² (parabola), f(x) = x³ (cubic).

④ Rational Function

f(x) = p(x)/q(x) where p(x) and g(x) are polynomials and g(x) ≠ 0. Example: f(x) = 1/x, Domain = R–{0}, Range = R–{0}.

⑤ Modulus Function

f(x) = |x| = x if x ≥ 0; –x if x < 0. Domain = R, Range = [0, ∞). V-shaped graph.

⑥ Signum Function

f(x) = 1 if x > 0; 0 if x = 0; –1 if x < 0. Domain = R, Range = {–1, 0, 1}.

⑦ Greatest Integer Function

f(x) = [x] = greatest integer ≤ x. Also called floor function. Example: [2.7] = 2, [–1.3] = –2. Graph: step function.

🖼️

[ Image: Graphs of identity, modulus, signum, and greatest integer functions — add here ]

Identity: f(x)=x, graph through origin
Modulus: f(x)=|x|, V-shape
Signum range = {-1,0,1}
GIF: [2.9]=2, [-1.1]=-2

🎯 Practice MCQs

3 Questions
10The range of the signum function f : R → R is:
AR
B[0, ∞)
C{–1, 0, 1}
D{0, 1}
Answer: C
The signum function outputs exactly three values: 1 for positive x, 0 for x=0, and –1 for negative x. So Range = {–1, 0, 1}.
11The value of the greatest integer function [–2.5] is:
A–2
B–3
C2
D3
Answer: B
[x] is the greatest integer LESS THAN OR EQUAL to x. The greatest integer ≤ –2.5 is –3 (since –3 < –2.5 < –2, the greatest integer not exceeding –2.5 is –3).
12The domain and range of f(x) = 1/x (x ∈ R – {0}) are:
ADomain = R, Range = R
BDomain = R – {0}, Range = R
CDomain = R – {0}, Range = R – {0}
DDomain = R, Range = R – {0}
Answer: C
f(x) = 1/x is undefined at x = 0, so domain = R – {0}. For any non-zero y, x = 1/y gives a valid input — so f(x) takes all values except 0. Range = R – {0}.
ADVERTISEMENT
f+g

2.5 Algebra of Real Functions

For functions f : X → R and g : X → R, we define the following operations:

+

Sum: (f + g)(x) = f(x) + g(x), for all x ∈ X

Difference: (f – g)(x) = f(x) – g(x), for all x ∈ X

×

Product: (fg)(x) = f(x) · g(x), for all x ∈ X (pointwise multiplication)

k

Scalar multiple: (kf)(x) = k · f(x), for all x ∈ X, where k is a real number

÷

Quotient: (f/g)(x) = f(x)/g(x), for all x ∈ X where g(x) ≠ 0

🖼️

[ Image: Example illustration of function operations on graphs — add here ]

Example: If f(x) = x² and g(x) = 2x + 1:

(f+g)(x) = x²+2x+1
(f-g)(x) = x²-2x-1
(fg)(x) = 2x³+x²
(f/g)(x) = x²/(2x+1), x≠-½

🎯 Practice MCQs

3 Questions
13If f(x) = x² and g(x) = 2x + 1, then (f + g)(2) is:
A8
B9
C9
D4
Answer: C
(f + g)(x) = x² + 2x + 1
(f + g)(2) = 4 + 4 + 1 = 9.
Alternatively: f(2) + g(2) = 4 + 5 = 9 ✓
14If f(x) = √x and g(x) = x (over non-negative reals), then (fg)(x) equals:
A√x + x
Bx
Cx^(3/2)
D
Answer: C
(fg)(x) = f(x) · g(x) = √x · x = x · x^(1/2) = x^(1 + 1/2) = x^(3/2).
15Let f(x) = x + 1 and g(x) = 2x – 3. The value of (f/g)(2) is:
A–3
B1
C3
D–1
Answer: C
(f/g)(x) = f(x)/g(x) = (x+1)/(2x–3).
(f/g)(2) = (2+1)/(2·2–3) = 3/(4–3) = 3/1 = 3.
ADVERTISEMENT

🚀 Ace Your AAI ATC Exam!

Free video lectures, worksheets & direct doubt support — all at Aviate Learnings.