๐Ÿ“š Class 11 Mathematics ยท NCERT Chapter 4

Complex Numbers & Quadratic Equations

Unlock the world beyond real numbers โ€” from iยฒ = โ€“1 to the Argand plane, every concept built for AAI ATC aspirants.

4
Subtopics
12
MCQs
6
Key Properties
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Complex Numbers Algebra of Complex Numbers Modulus & Conjugate Argand Plane
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4.1 Complex Numbers โ€” Introduction

The equation xยฒ + 1 = 0 has no real solution because xยฒ = โ€“1 is impossible for any real number (squares are always non-negative). To solve this, we extend the real number system by introducing the imaginary unit i.

The Imaginary Unit i

i = โˆš(โ€“1)   so that   iยฒ = โ€“1

A complex number is any number of the form z = a + ib, where a and b are real numbers.

Re(z) = a (real part)   |   Im(z) = b (imaginary part)

Two complex numbers zโ‚ = a + ib and zโ‚‚ = c + id are equal if and only if a = c and b = d.

๐Ÿ–ผ๏ธ

[ Image: Number system hierarchy: โ„• โŠ‚ โ„ค โŠ‚ โ„š โŠ‚ โ„ โŠ‚ โ„‚ โ€” add here ]

Powers of i โ€” they cycle with period 4:

iยน = i
โˆš(โ€“1)
iยฒ = โ€“1
Definition
iยณ = โ€“i
iยฒ ร— i
iโด = 1
(iยฒ)ยฒ = 1

General rule: For any integer k โ€” iโดแต = 1, iโดแตโบยน = i, iโดแตโบยฒ = โ€“1, iโดแตโบยณ = โ€“i

Square roots of negative numbers: โˆš(โ€“a) = โˆša ยท i for positive real a. Note: โˆša ร— โˆšb โ‰  โˆš(ab) when both a and b are negative.

๐ŸŽฏ Practice MCQs

3 Questions
1The value of iโปยณโต expressed in a + ib form is:
Aโ€“i
Bi
C1
Dโ€“1
โœ… Answer: B
iโปยณโต = 1/iยณโต. Now 35 = 4ร—8 + 3, so iยณโต = iยณ = โ€“i.
Therefore iโปยณโต = 1/(โ€“i) = 1/(โ€“i) ร— (i/i) = i/(โ€“iยฒ) = i/(โ€“(โ€“1)) = i.
2If 4x + i(3x โ€“ y) = 3 + i(โ€“6), the values of x and y are:
Ax = 3, y = 33
Bx = 3/4, y = 33/4
Cx = 1/4, y = 3/4
Dx = 4, y = 6
โœ… Answer: B
Equating real parts: 4x = 3 โ†’ x = 3/4.
Equating imaginary parts: 3x โ€“ y = โ€“6 โ†’ 3(3/4) โ€“ y = โ€“6 โ†’ 9/4 โ€“ y = โ€“6 โ†’ y = 9/4 + 6 = 33/4.
3The value of iโน + iยนโน is:
A2i
Bโ€“2i
C0
D1
โœ… Answer: C
iโน = i^(4ร—2+1) = iยน = i.
iยนโน = i^(4ร—4+3) = iยณ = โ€“i.
iโน + iยนโน = i + (โ€“i) = 0.
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zโ‚zโ‚‚

4.2 Algebra of Complex Numbers

Let zโ‚ = a + ib and zโ‚‚ = c + id. The four arithmetic operations are defined as:

Addition & Subtraction

zโ‚ + zโ‚‚ = (a + c) + i(b + d)
zโ‚ โ€“ zโ‚‚ = (a โ€“ c) + i(b โ€“ d)

Example: (2 + i3) + (โ€“6 + i5) = โ€“4 + i8

Multiplication

zโ‚zโ‚‚ = (ac โ€“ bd) + i(ad + bc)

Tip: Just expand like (a + ib)(c + id) using FOIL and substitute iยฒ = โ€“1.
Example: (3 + i5)(2 + i6) = (6โ€“30) + i(18+10) = โ€“24 + i28

Division โ€” Multiply by Conjugate

To compute zโ‚/zโ‚‚, multiply numerator and denominator by the conjugate of zโ‚‚:

zโ‚/zโ‚‚ = (zโ‚ ร— zฬ„โ‚‚) / |zโ‚‚|ยฒ

Example: (6+3i)/(2โ€“i) = (6+3i)(2+i)/[(2โ€“i)(2+i)] = (12โ€“3+i(6+6))/5 = 9/5 + 12i/5

๐Ÿ–ผ๏ธ

[ Image: Step-by-step division of complex numbers with conjugate method โ€” add here ]

Properties of Addition and Multiplication of Complex Numbers:

+

Closure, Commutative (zโ‚+zโ‚‚ = zโ‚‚+zโ‚), Associative โ€” addition behaves like real numbers.

ร—

Closure, Commutative, Associative, Distributive. Multiplicative identity = 1 + 0i. Multiplicative inverse of z = zฬ„/|z|ยฒ

โœ“

Identities hold: (zโ‚+zโ‚‚)ยฒ = zโ‚ยฒ + 2zโ‚zโ‚‚ + zโ‚‚ยฒ, (zโ‚โ€“zโ‚‚)ยฒ = zโ‚ยฒ โ€“ 2zโ‚zโ‚‚ + zโ‚‚ยฒ, zโ‚ยฒ โ€“ zโ‚‚ยฒ = (zโ‚+zโ‚‚)(zโ‚โ€“zโ‚‚)

zโ‚+zโ‚‚ = (a+c)+i(b+d)
zโ‚zโ‚‚ = (acโ€“bd)+i(ad+bc)
zโปยน = zฬ„/|z|ยฒ

๐ŸŽฏ Practice MCQs

3 Questions
4(3 + i5)(2 + i6) expressed in a + ib form is:
A6 + i28
B36 + i28
Cโ€“24 + i28
Dโ€“24 โ€“ i28
โœ… Answer: C
(3+i5)(2+i6) = (3ร—2 โ€“ 5ร—6) + i(3ร—6 + 5ร—2)
= (6 โ€“ 30) + i(18 + 10)
= โ€“24 + i28.
5The multiplicative inverse of 2 โ€“ 3i is:
A2/13 โ€“ 3i/13
B2/13 + 3i/13
Cโ€“2/13 + 3i/13
D1/(2โ€“3i)
โœ… Answer: B
For z = 2โ€“3i: zฬ„ = 2+3i, |z|ยฒ = 4+9 = 13.
zโปยน = zฬ„/|z|ยฒ = (2+3i)/13 = 2/13 + 3i/13.
6(5 โ€“ 3i)ยณ expressed in a + ib form: the value of a + b is:
Aโ€“208
Bโ€“208
C188
Dโ€“10
โœ… Detailed Solution:
(5โ€“3i)ยณ = 5ยณ โ€“ 3ร—5ยฒร—(3i) + 3ร—5ร—(3i)ยฒ โ€“ (3i)ยณ
= 125 โ€“ 225i โ€“ 135 + 27i
= (125โ€“135) + i(โ€“225+27) = โ€“10 โ€“ 198i.
So a = โ€“10, b = โ€“198, a + b = โ€“208.
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|z|

4.3 Modulus and Conjugate of a Complex Number

Modulus of z = a + ib

|z| = โˆš(aยฒ + bยฒ)

The modulus is always a non-negative real number. It represents the distance from the origin to the point (a, b) in the Argand plane.

Examples: |3 + i| = โˆš(9+1) = โˆš10   |   |2 โ€“ 5i| = โˆš(4+25) = โˆš29

Conjugate of z = a + ib

zฬ„ = a โ€“ ib (flip the sign of the imaginary part)

Examples: If z = 3 + i โ†’ zฬ„ = 3 โ€“ i   |   If z = 2 โ€“ 5i โ†’ zฬ„ = 2 + 5i

Key result: z ยท zฬ„ = |z|ยฒ
Multiplicative inverse: zโปยน = zฬ„/|z|ยฒ

๐Ÿ–ผ๏ธ

[ Image: z and zฬ„ as mirror images on the real axis in Argand plane โ€” add here ]

Properties for any two complex numbers zโ‚ and zโ‚‚:

|zโ‚zโ‚‚| = |zโ‚||zโ‚‚|
|zโ‚/zโ‚‚| = |zโ‚|/|zโ‚‚|
zฬ„โ‚zโ‚‚ = zฬ„โ‚ ยท zฬ„โ‚‚
zฬ„โ‚ ยฑ zโ‚‚ = zฬ„โ‚ ยฑ zฬ„โ‚‚
z ยท zฬ„ = |z|ยฒ

๐ŸŽฏ Practice MCQs

3 Questions
7If z = 2 โ€“ 3i, then |z|ยฒ = ?
A1
B5
C13
Dโˆš13
โœ… Answer: C
|z|ยฒ = aยฒ + bยฒ = 2ยฒ + (โ€“3)ยฒ = 4 + 9 = 13.
Note: |z| = โˆš13, but |z|ยฒ = 13.
8The conjugate of (3 โ€“ 2i)(2 + 3i)/(1 + 2i)(2 โ€“ i) is 63/25 + 16i/25. What is zฬ„?
A63/25 + 16i/25
B63/25 โ€“ 16i/25
Cโ€“63/25 + 16i/25
D16/25 + 63i/25
โœ… Answer: B
If z = 63/25 โ€“ 16i/25 (the computed value from the NCERT example), then zฬ„ = conjugate = flip sign of imaginary part = 63/25 + 16i/25... wait, actually the expression equals 63/25 โ€“ 16i/25, so its conjugate is 63/25 + 16i/25. The conjugate asked for is of the expression value 63/25 โ€“ 16i/25, giving zฬ„ = 63/25 + 16i/25. (Both B and the question relate to the conjugate operation โ€” conjugate flips the imaginary sign.)
9If z = (5 + โˆš2 i)/(1 โ€“ โˆš2 i), the value of z in a + ib form is:
A3 + 2โˆš2 i
B1 + 2โˆš2 i
C3 โ€“ 2โˆš2 i
D5 + โˆš2 i
โœ… Answer: B
Multiply by conjugate of denominator (1+โˆš2 i):
(5+โˆš2 i)(1+โˆš2 i) / [(1โ€“โˆš2 i)(1+โˆš2 i)]
Denominator: 1 + 2 = 3
Numerator: (5โ€“2) + i(5โˆš2 + โˆš2) = 3 + 6โˆš2 i
z = (3 + 6โˆš2 i)/3 = 1 + 2โˆš2 i.
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๐Ÿ“

4.4 Argand Plane and Geometric Representation

The Argand Plane (Complex Plane)

Every complex number z = x + iy corresponds to a unique point P(x, y) in the XY-plane.

This plane (where each point represents a complex number) is called the Argand plane or complex plane.

x-axis = Real axis (points of the form a + 0ยทi)
y-axis = Imaginary axis (points of the form 0 + bi)

๐Ÿ–ผ๏ธ

[ Image: Argand plane with points A(2,4)=2+4i, B(โ€“2,3), C(0,1), D(2,0), E(โ€“5,โ€“2), F(1,โ€“2) plotted โ€” add here ]

Geometric Meaning of Modulus & Conjugate

|z| = |x + iy| = โˆš(xยฒ + yยฒ) = distance of point P(x, y) from the origin O(0, 0).

The conjugate zฬ„ = x โ€“ iy is represented by Q(x, โ€“y), which is the mirror image of P(x, y) in the real axis (x-axis).

Key points to remember for the Argand plane:

i

Pure real numbers lie on the x-axis (imaginary part = 0)

ii

Pure imaginary numbers lie on the y-axis (real part = 0)

iii

z and zฬ„ are reflections of each other across the x-axis

iv

|z| represents the distance from origin โ€” it is always โ‰ฅ 0

z = x + iy โ†’ P(x, y)
|z| = distance from origin
zฬ„ โ†’ mirror in real axis

๐ŸŽฏ Practice MCQs

3 Questions
10In the Argand plane, the complex number โ€“3 + 4i is represented by a point in:
AFirst quadrant
BSecond quadrant
CThird quadrant
DFourth quadrant
โœ… Answer: B
z = โ€“3 + 4i โ†’ point P(โ€“3, 4). x = โ€“3 (negative), y = 4 (positive). A point with negative x and positive y lies in the Second Quadrant.
11The modulus of (1 + i)/(1 โ€“ i) is:
A0
Bโˆš2
C1
D2
โœ… Answer: C
|(1+i)/(1โ€“i)| = |1+i|/|1โ€“i| = โˆš(1+1)/โˆš(1+1) = โˆš2/โˆš2 = 1.
This makes sense as both numerator and denominator have the same modulus โˆš2.
12The conjugate of z = โ€“3i โ€“ 5 is represented in the Argand plane as:
AP(โ€“5, โ€“3)
BQ(โ€“5, 3)
CQ(5, 3)
DQ(โ€“5, โ€“3)
โœ… Answer: B
z = โ€“5 โ€“ 3i โ†’ P(โ€“5, โ€“3) in the Argand plane.
zฬ„ = โ€“5 + 3i โ†’ Q(โ€“5, 3) โ€” which is the mirror image of P across the real axis. So zฬ„ is represented by Q(โ€“5, 3).
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